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From Mathematics: Calculus
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Due on Oct. 12, 2008
Asked on Oct 09, 2008 at 7:44:53PM

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Given f(x) = (1.3x^4-.02x^3+.25x^2-x+5)^3. Evaluate the first derivative when x = -1, x = 0, x = 1, x=2, and x=3.

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Posted on Oct 09, 2008 at 8:13:48PM

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Preview: ... en f(x) = (1.3x^4-.02x^3+.25x^2-x+5)^3. Evaluate the first d ...

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Posted on Oct 09, 2008 at 8:24:36PM

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Preview: ... 162.143372 when x = 0, f'(0)=3*25*(-1)=-75 when x = 1, f'(1)= 3*(5.53)^2*(4.64)=425.686128< ...

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Posted on Oct 09, 2008 at 11:29:46PM

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Preview: ... and finf f'(x) f'(-1) = -1162.143372 f'(0) = -75 f'( ...

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$1.50 here is the solution properly explained.

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Posted on Oct 10, 2008 at 9:36:16PM

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Preview: ... +5)^2 *(5.2-.06+.50-1) =3(5.53)^2 * (4.64) =3*30.5809 * (4.64) =425.6861 f'(2) = 3(20.8-.16+1-2+5)^2 *( ...

The full tutorial is about 129 words long .