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Due on Nov. 08, 2009
Asked on Nov 05, 2009 at 8:54:23PM

Q:

A ladder 10 feet long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 7 feet per second, how fast is the top of the ladder sliding down the wall ( in feet per second) when the bottom of the ladder is 6 feet from the wall?

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thementoronline
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$3.00 Calculus answer

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Posted on Nov 05, 2009 at 9:18:28PM

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Preview: ... ^2 + y^2 = 100. Using implicit differentiation and the chain rule we have 2 x (d x/d t)+ 2 y (d y/d t)= 0. By solvi ...

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Posted on Nov 05, 2009 at 10:46:37PM

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Preview: ... from the wall be x feet. Let the distance of the top of the ladder from the floor be y feet. ...

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kamleshsingh
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Posted on Nov 06, 2009 at 01:27:09PM

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Preview: ... {sqrt->square root) Differentiate with respect to t ...

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Posted on Nov 06, 2009 at 6:36:30PM

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Preview: ... e the ...

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Siyao

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$0.75 the easiest way and the most complete answer

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Posted on Nov 07, 2009 at 1:08:56PM

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Preview: ... bottom move away from the wall is dx/dt=7, the eq uation we know from the right triangle is th at y= âˆš10 2-x 2 Â Then, we differentiate with respect to x, dy/dt=1/ ...

The full tutorial is about 153 words long .