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Due on Nov. 05, 2009
Asked on Nov 05, 2009 at 9:05:19PM

Q:

A conical salt spreder is spreading salt at a rate of 2 cubic feet per minute. The diameter of the base of the cone is 4 feet and the height of the cone is 5 feet.

How fast is the height of the salt in the spreader decreasing when the height of the salt in the spreader is 3 feet? (give answer in feet per minute)

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GangadharSenapati

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Posted on Nov 05, 2009 at 9:28:18PM

A:
Preview: ... et dV/dt = (1/3)∏R 2 dh/dt = 2 ...

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sudipta

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Posted on Nov 05, 2009 at 11:04:28PM

A:
Preview: ... π r 2 h So, dV/dt = (1/3)π h (2r)(dr/dt) + (1/3) π r 2 (dh/dt) Again, r/h = (4/2)/5 = 2/5 = 0.4 ...

The full tutorial is about 93 words long .