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tracie34_19992003
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$1.00 physics

  • From Physics: General-Physics
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  • Due on Nov. 08, 2009
  • Asked on Nov 06, 2009 at 10:30:26PM
Q:

A dentist's drill starts from rest. After 2.80 s of constant angular acceleration it turns at a rate of 2.8 <!--filtered--> 104 rev/min.

(a) Find the drill's angular acceleration.
1 rad/s2

(b) Determine the angle (in radians) through which the drill rotates during this period.
2 rad
 


   
   
   
   
 
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Onlinetutor365
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$1.00 A dentists drill starts from rest. After 2.80 s of constant angular acceleration it turns at a rate of 2.8 <!--filter

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  • Posted on Nov 06, 2009 at 11:17:15PM
A:
Preview: ... 1 = 0,             ω 2 = 2.8x104 rpm                = 2.8rpm x2π rad/revx1/60 s/min x10 4                 = 0.2 ...

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