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tracie34_19992003

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Due on Nov. 08, 2009
Asked on Nov 06, 2009 at 11:14:14PM

Q:

A 45n force pulled a 3 kg mass at an angle of 40 degrees above horizontal through a distance of 15 m on a surface with coefficient of kinetic friction Uk=0.28. Complete the following :

Gravitational force=

Normal force=

Frictional force=

work done by applied force=

work done by Gravitational force=

Work done by Normal Force=

work done by Frictional force=

net work done by mass=

gain in Kinetic energy of the mass=

final velocity of the mass=

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Posted by:

mellisa

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Posted on Nov 06, 2009 at 11:26:32PM

A:
Preview: ... ons Â work done by applied force=45cos40x15=584.6 joules work done by Gravitational force=0 Work done by Normal Force=0 ...

The full tutorial is about 76 words long .

Posted by:

GangadharSenapati

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Posted on Nov. 07, 2009 at 12:17:11AM

A:
Preview: ... Angle = Î¸ = 40 Â Â Coefficient of kinetic friction Î¼ k = 0.28Â Gravitational force = Mg = 3 Ã— 9.8 = 29.4 Newton N + F sinÎ¸ = Mg N = 29.4 - 45 sin 40 = 0.47456 Newton No ...

The full tutorial is about 198 words long .