parabola- focus, directrix, graph, and eccentricy- x = y^2 + 2y - 8

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burnt_umber
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$1.00 parabola- focus, directrix, graph, and eccentricy- x = y^2 + 2y - 8

From Mathematics: Algebra
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Due on Nov. 19, 2008
Asked on Nov. 16, 2008 at 09:17:30AM

Q:
Sketch the graph and give the eccentricity. Lable focus and directrix. Explain process step-wise. Thanks!

x = y^2 + 2y - 8

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shri21

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$4.00 Parabola - Properties and Graph

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Posted on Nov. 16, 2008 at 09:34:02AM

A:
Preview: ... form x = a(y - k)^2 + h<br><br>h = -9, k = -1, a = 1<br> ...

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sudipta

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$2.50 Graph and all intermediate parts

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Posted on Nov. 16, 2008 at 11:32:44AM

A:
Preview: ... t (h + a, k), i.e. (-9 + 1/4, -1), which is (-8.75, -1).<br>The equation of the directrix is given by x ...

The full tutorial is about 110 words long plus attachments.

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Parabola.doc (47K) (Preview)