parabolic inequality - StudentOfFortune.com

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$5.00 parabolic inequality

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Due on Dec. 01, 2008
Asked on Nov. 28, 2008 at 07:38:12AM

Q:
The question is about a parabolic inequality,-x^2+2x+3 is greater than or equal to 0. I have the formulas, I plugged in the numbers, but the graph is not right, so my numbers must be wrong. Please help! I have the axis of symmetry as . Is this correct? I have the vertex of y=4? I have y-intercept od (0,3)? I have X intercepts of (-1,0) and (3,0). Please tell me where I am going wrong...Thanks. Please also confirm where to shade and the range, thanks.

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speedmath
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Posted on Nov. 28, 2008 at 08:08:45AM

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Preview: ... ull Solut ...

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Full Solution as Inequality.pdf (9K) (Preview)
Full Solution as Polynominals.pdf (13K) (Preview)
Inequality's Graph.pdf (10K) (Preview)
Polynomials' Graph.pdf (8K) (Preview)

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Posted on Nov. 28, 2008 at 08:37:16AM

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Preview: ... metry by using x=-b/2a. in this case, x=-2/2(-1) = 1 x=1 is the axis of symmetry. Th ...

The full tutorial is about 77 words long plus attachments.

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graph of parabolic inequality.doc (27K) (Preview)

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shri21

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Posted on Nov. 28, 2008 at 09:27:38AM

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Preview: ... <= 0 x(x + 1) - 3(x + 1) <= 0 (x + 1)(x - 3) <= 0 This ...

The full tutorial is about 76 words long plus attachments.

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Graph.doc (24K) (Preview)