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Preview: ... +2)(x-1))/((x+1)) to get (3(x+2))/((x+3)).<br>((3(x+2))/(x+3))<br><br>Remove the parentheses around the expression (3(x+2))/((x+3)).<br>(3(x+2))/(x+3)<br><br>==================================<br>Question #3 / 18<br>Divide. Write your answer in lowest terms. <br> <br>(((15yz)/(2y)))/(((9z)/(10y)))<br><br>Remove all extra parentheses from the expression.<br>(10y)/(9z)*(15yz)/(2y)<br><br>Remove the common factors that were cancelled out.<br>(10y)/(9z)*(15z)/(2)<br><br>Remove the common factor of 2 from the numerator of the first term (10y)/(9z) and the denominator of the second term (15z)/(2).<br>(5y)/(9z)*15z<br><br>Reduce the expression by removing the common factor of 3z in the denominator of the first term (5y)/(9z) and the second term 15z.<br>(5y)/(3)*5<br><br>Multiply (5y)/(3) by 5 to get (25y)/(3).<br>(25y)/(3)<br><br>==================================<br>Question #4 / 18<br>Express the following compound fraction in lowest terms: <br>. <br> <br>(((14t^(3)u)/(5rs^(3))))/(((7t^(5)u^(4))/(10s^(4))))<br><br>Remove all extra parentheses from the expression.<br>(10s^(4))/(7t^(5)u^(4))*(14t^(3)u)/(5rs^(3))<br><br>Remove the common factor of 5s^(3) from the numerator of the first term (10s^(4))/(7t^(5)u^(4)) and the denominator of the second term (14t^(3)u)/(5rs^(3)).<br>(2s)/(7t^(5)u^(4))*(14t^(3)u)/(r)<br><br>Reduce the expression by removing the common factor of 7t^(3)u in the denominator of the first term (2s)/(7t^(5)u^(4)) and the numerator of the second term (14t^(3)u)/(r).<br>(2s)/(t^(2)u^(3))*(2)/(r)<br><br>Multiply (2s)/(t^(2)u^(3)) by (2)/(r) to get (4s)/(rt^(2)u^(3)).<br>(4s)/(rt^(2)u^(3))<br><br>==================================<br>#5<br> <br>((6z-2w)/(9z))-((2z-3w)/(9z))<br><br>Factor out the GCF of 2 from each term in the polynomial.<br>((2(3z)+2(-w))/(9z))-((2z-3w)/(9z))<br><br>Factor out the GCF of 2 from 6z-2w.<br>((2(3z-w))/(9z))-((2z-3w)/(9z))<br><br>Multiply -1 by each term inside the parentheses.<br>(2(3z-w))/(9z)-(3w-2z)/(9z)<br><br>The numerators of expressions that have equal denominators can be combined. In this case, (2(3z-w))/(9z) and -((3w-2z))/(9z) have the same denominator of 9z, so the numerators can be combined.<br>(2(3z-w)-(3w-2z))/(9z)<br><br>Simplify the numerator of the expression.<br>(8z-5w)/(9z)<br><br>==================================<br>#6<br>Express as a single fraction in lowest terms:<br> <br>((9z-5t)/(2z))+((6z-4t)/(3z))-8<br><br>Factor out the GCF of 2 from each term in the polynomial.<br>((9z-5t)/(2z))+((2(3z)+2(-2t))/(3z))-8<br><br>Factor out the GCF of 2 from 6z-4t.<br>((9z-5t)/(2z))+((2(3z-2t))/(3z))-8<br><br>Remove the parentheses that are not needed from the expression.<br>(9z-5t)/(2z)+(2(3z-2t))/(3z)-8<br><br>Multiply each term by a factor of 1 that will equate all the denominators. In this case, all terms need a denominator of 6z. The ((9z-5t))/(2z) expression needs to be multiplied by ((3))/((3)) to make the denominator 6z. The (2(3z-2t))/(3z) expression needs to be multiplied by ((2))/((2)) to make the denominator 6z.<br>(9z-5t)/(2z)*(3)/(3)+(2(3z-2t))/(3z)*(2)/(2)-8*(6z)/(6z)<br><br>Multiply the expression by a factor of 1 to create the least common denominator (LCD) of 6z.<br>((9z-5t)(3))/(6z)+(2(3z-2t))/(3z)*(2)/(2)-8*(6z)/(6z)<br><br>Multiply the expression by a factor of 1 to create the least common denominator (LCD) of 6z.<br>((9z-5t)(3))/(6z)+(2(3z-2t)(2))/(6z)-8*(6z)/(6z)<br><br>Multiply the expression by a factor of 1 to create the least common denominator (LCD) of 6z.<br>((9z-5t)(3))/(6z)+(2(3z-2t)(2))/(6z)-(8*6z)/(6z)<br><br>Multiply 8 by 6z to get 48z.<br>((9z-5t)(3))/(6z)+(2(3z-2t)(2))/(6z)-(48z)/(6z)<br><br>The numerators of expressions that have equal denominators can be combined. In this case, ((9z-5t)(3))/(6z) and (2(3z-2t)(2))/(6z) have the same denominator of 6z, so the numerators can be combined.<br>((9z-5t)(3)+2(3z-2t)(2)-(48z))/(6z)<br><br>Simplify the numerator of the expression.<br>(-9z-23t)/(6z)<br><br>==================================<br>Question #7 / 18<br>Add and simplify: <br> <br>(-(2)/(x-1))+((1-x)/(x))<br><br>Reorder the polynomial 1-x alphabetically from left to right, starting with the highest order term.<br>-(2)/(x-1)+(- ...
The full tutorial is about 2457 words long .
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- Posted on Nov 29, 2008 at 3:24:35PM
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The full tutorial is about 32 words long plus attachments.
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week three 18 questions.doc (51K) (Preview)
