$7.00 Solution to first four problems
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- Posted on May 04, 2008 at 10:15:03PM
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Preview: ... ttached file for figures. <br><br>Suppose that the sum of the measures of the vertex<br>angles of a convex polygon is ...
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$39.00 All Questions Answered
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- Posted on May 05, 2008 at 01:30:54PM
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Preview: ... angle<br>(b) as shown<br>(c) as shown<br><br>Q4<br>Use Pythagoras' theorem.<br>1743 * 1743 + 1828 * 1828 = 6379633<br>2525 * 2525 = 6375625<br>they are not the same.<br>Hence the triangle is not a right triangle.<br><br>Q5<br>(a)<br>sum of all angles = (20-2) x 180 = 3240 degrees<br>sum of each angle = 3240 / 20 = 162 degrees<br>(b)<br>sum of all angles = (37-2) x 180 = 6300 degrees<br>sum of each angle = 6300 / 37 = 170.27 degrees<br><br>Q6<br>(a) 4 times larger.<br>Let the radius of the original circle be r.<br>The area = pi * r * r<br>Radius of the doubled circle is 2r.<br>The area = pi * (2r) * (2r) = 4 * pi * r * r<br>= 4 * area of original circle.<br>(b) 25 times larger.<br>Radius of the new circle = 5r.<br>The area = pi * (5r) * (5r) = 25 * pi * r * r<br>= 25 * area of the original circle<br>(c) n*n times larger.<br>Radius of the new circle = nr.<br>The area = pi * (nr) * (nr) = (n*n) * pi * r * r<br>= (n*n) * area of the original circle<br><br>Q7<br>Attachment: Q7.gif<br>In the figure, Ac = 6cm and BD = 8cm.<br>Since the diagonals of a rhombus are perpendicular to each other,<br>angle AEB is 90 degrees.<br>Moreover, the diagonals of a rhombus bisect each other, therefore<br>BE = BD / 2 = 4cm.<br>Area of triangle ABC = (BE * AC) / 2 = (4 * 6) / 2 = 12 cm sq.<br>Similarly, area of triangle ADC = 12 cm sq.<br>Therefore, area of rhombus = 12 + 12 = 24 cm sq.<br><br>Q8<br>Attachment: Q7.gif (not Q8.gif)<br>In the figure, Ac = d1 an ...
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geom.zip (83K)
$40.00 Full solution with exhaustive explanantions and all diagrams shown
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- Posted on May 05, 2008 at 11:03:38PM
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Preview: ... olutions and the diagr ...
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Geometry.doc (374K) (Preview)