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$5.00 Calculus

  • From Mathematics: Calculus
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  • Due on Jan. 30, 2009
  • Asked on Jan 30, 2009 at 3:14:12PM
Q:
I have done most of this assignment the best way that I know how but I am struggling with some of the problems. If someone could help me with problems 2-5 and 18. You can either show the work or you can just give me an accurate answer so I can try to work them out myself.

Thanks
 
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Spring2009-Math1242-700.trlee1.WW27_FTC.pdf (66K)


   
   
   
   
 
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joaog
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$5.00 Answers

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  • Posted on Jan 30, 2009 at 3:40:14PM
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Preview: ... maximum is for x=0 and is 4*3 = 12.<br><br>3) f'(x) = x^3 + 3x^2 + 2 thus f''(x) = 3x^2 + 6x<br><br>4) f'(x) = 4x^3*x^16 - x^4 ...

The full tutorial is about 99 words long .
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$1.00 [Q3] 3x^2+6x

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  • Posted on Jan 30, 2009 at 4:05:46PM
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Preview: ... ...

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$1.00 [Q4] 4X^19-x^4

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Preview: ... Q4] 4X^1 ...

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$5.00 solutions

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  • Posted on Jan 30, 2009 at 4:12:42PM
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Preview: ... <br><br>then differentiate(the first int is differentiated with the chain rule)<br><br>(t^4)^4*4t^3-t^4<br><br>which gives<br><br>4t^19-t^4<br><br>5. at the max we have f'(t)=0<br><br>therefore<br><br>(t^2-9)/(1+cos(t ...

The full tutorial is about 102 words long .
   
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