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what is the correct substitution in the quadratic formula for the solution of the following: 8x^2+3a^2=10ax (a) x=-10+(sqrt)100a^2-4x3a^2x10 / 2x8 (b)x= -3a-(sqrt)9a^2-4x8x10a / 2x8 (c) x= 10+(sqrt)100-4x8x3 / 2x8 (d) x= 10a-(sqrt)100a^2-4x8x3a^2 / 2x8
 


   
   
   
   
 
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  • Posted on Jan 30, 2009 at 3:30:11PM
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Preview: ... formula for the solu ...

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  • Posted on Jan 30, 2009 at 3:31:42PM
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Preview: ... + 3a^2 = 0<br>=> x = [-(-10a) ± sqr ...

The full tutorial is about 30 words long .
   
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