A man stands on the roof of a 19.0 m tal

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eznaoum
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$5.00 A man stands on the roof of a 19.0 m tal

From Physics: General-Physics
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Due on Jan. 31, 2009
Asked on Jan 31, 2009 at 3:56:42PM

Q:
A man stands on the roof of a 19.0 m tall building and throws a rock with a velocity of magnitude 24.0m/s at an angle of 42.0 degrees above the horizontal. Ignore air resistance. Calculate the magnitude of the velocity of the rock just before it strikes the ground. Calculate the horizontal distance from the base of the building to the point where the rock strikes the ground.

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gorgo20
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Posted on Jan 31, 2009 at 4:35:03PM

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Preview: ... hen the ball hits the gr ...

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Posted on Jan 31, 2009 at 4:56:04PM

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Preview: ... egative root. So, the rock strikes the ground after 4.2 seconds. Now, the horizontal component of the velocity remains unchanged at 17.8355 m/s The vertical component of the velocity becomes = u - gt = [16.0591 - 9.8 * 4.2] m/s = -25.1 m/s So, the magnitude of the veloci ...

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mellisa

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Posted on Jan 31, 2009 at 7:07:48PM

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Preview: ... EE FI ...

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