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cothranaimeel
cothranaimeel
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$1.00 more with intermediate value thm stuff...

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1. Let a < b. Prove that for any continuous function f : [a, b] -> [a, b]there exists c in [a, b] such that f(c) = c.


The following is a more general version of the previous theorem.


2. Let a < b. Prove that if f : [a, b] -> R and g : [a, b] -> R are continuous, f(a) <= g(a), and f(b) >= g(b) then there exists c in [a, b] such that f(c) = g(c).
 


   
   
   
   
 
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gorgo20
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  • Posted on Feb 01, 2009 at 12:12:42PM
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Preview: ... set <br>{x in [a,b] | f(x)<x} such <br>that xn converges to c. Therefore taking limits in the inequality f(xn)<xn we get f(c)<=c.<br><br>Now, if we assume that f(c)<c,first, c is different than a<br>because f(a)>=a, and second, by the continuity <br><br>of f, since f(c)<c, we can pick a small epsilon>0 so that<br>c-epsilon belongs to [a,b] and <br>f(c-epsilon)<c-epsilon<br> <br>(you see, f(x)-x is co ...

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