$2.00 100% correct answer comming from a PhD in physics
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- Posted on Mar. 02, 2009 at 12:39:31AM
A:
Preview: ... tational acceleration on the moo ...
The full tutorial is about 23 words long .
$1.75 NEAT EXPLANATION OF THE FACTS
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- Posted on Mar. 02, 2009 at 12:46:29AM
A:
Preview: ... motion<br>V^2 =0 +2*gmoon*h, gmoo ...
The full tutorial is about 23 words long .
$1.50 Value for your money
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- Posted on Mar. 02, 2009 at 12:51:01AM
A:
Preview: ... for uniform accelerated motion<br> ...
The full tutorial is about 23 words long .
$0.75 please see it
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- Posted on Mar. 02, 2009 at 12:54:50AM
A:
Preview: ... he gravitational acceleration on ...
The full tutorial is about 23 words long .
$1.00 Your A+ answer!
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- Posted on Mar. 02, 2009 at 12:57:07AM
A:
Preview: ... use the eq for uniform accelerat ...
The full tutorial is about 23 words long .
$1.00 100%perfect step by step solution what u are seeking,plz see it
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- Posted on Mar. 02, 2009 at 01:10:11AM
A:
Preview: ... s of gravity. He jumped on the moon with an initial speed of 1.51m/s to a height of o.7m What amount of gravitatio ...
The full tutorial is about 97 words long .
$2.00 Full and complete solution with explanations of each step
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- Posted on Mar. 02, 2009 at 01:46:34AM
A:
Preview: ... t where the astronaut reaches his maximum height).<br><br>The formula relating acceleration and speed is:<br>a = (vf - vi)/t<br>where<br>vf is the final speed<br>vi is the initial speed<br>t is the time elapsed.<br>We know that vf is 0, and vi is 1.51m/s ...
The full tutorial is about 188 words long .
$1.50 A+ guarenteed, step by step done ,plz see it
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- Posted on Mar. 02, 2009 at 04:23:30AM
A:
Preview: ... t of gravitational acceleration of the moon be<br>g m / s ^ 2<br>then his initial spped , u = 1.51 m / s<br>height , h = .7 m<br>let his final speed be v m / sec <br>on that height his speed be v ...
The full tutorial is about 205 words long .
