$50.00 Limiting Reactants, Theoretical Yield and Percent Yield
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- Posted on Apr 13, 2009 at 11:08:13PM
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Preview: ... duced from a given amount of limiting reactant. The amount of product actually produced by the reaction is the actual yield and will usually be less than the theoretical yield. To express the efficiency of a reaction, chemists often calculate the percent yield, which is defined by:<br> <br><br>actual yield<br> <br><br>%yield<br> <br><br>=<br> <br><br>---------------------<br> <br><br>x<br> <br><br>100%<br> <br><br>theoretical yield<br> <br><br>Lets work through an example problem that will illustrate all of these concepts.<br><br>Example problem<br><br>Calculate the theoretical yield of C2H5Cl ...
The full tutorial is about 365 words long .
$10.00 Limiting Reactants
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- Posted on Apr 13, 2009 at 11:30:32PM
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Preview: ... xcess<br>which reactant produces the LEAST amount of H3PO3? water<br>your theoretical yield is the least amount of product ex ...
The full tutorial is about 113 words long .
$8.00 easy solution to your problem
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- Posted on Apr 14, 2009 at 06:25:57PM
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Preview: ... vely. <br><br>so 2 moles of h2 are going to react to 1 mole of o2. all of the o2 is used up, and you have left over h2, ...
The full tutorial is about 118 words long .
$75.00 Guaranteed A+ Answer
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- Posted on Apr 14, 2009 at 11:07:32PM
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Preview: ... ield<br> <br><br>Lets work through an example problem that will illustrate all of these concepts.<br><br>Example problem<br><br>Calculate the theoretical yield of C2H5Cl if 112 g of C2H5OH is reacted with 34.7 g of PCl3 based on the reaction below. If 23.7 g of C2H5Cl is produced, what is the percent yield?<br><br>3 C2H5OH + PCl3 ==> 3 C2H5Cl + H3PO3 <br><br>Solution<br><br>First we will assume that C2H5OH is the limiting reactant and calculate how much C2H5Cl would be formed. Then we will assume that PCl3 is the limiting reactant ...
The full tutorial is about 470 words long .
$20.00 Lesson and Samples
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- Posted on Apr 14, 2009 at 7:29:41PM
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Preview: ... icients are the numbers listed before each formula. This equation is already balanced, so refer to the tutorial on balancing equations if you need further help:<br><br>2 mol H2 / mol O2 <br><br>b. The actual ratio refers to the number of moles actually provided for the reaction. This may or may not be the same as the stoichiometric ratio. In this case, it is different:<br><br>1.50 mol H2 / 1.00 mol O2 = 1.50 mol H2 / mol O2 <br><br>c. Note that the actual ratio of smaller than the required ...
The full tutorial is about 418 words long .