probability 8-19,21 - StudentOfFortune.com

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$1.00 probability 8-19,21

From Mathematics: Probability , Mathematics: Combinatorics
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Due on May. 17, 2009
Asked on May 14, 2009 at 12:48:59PM

Q:
Suppose a family plans 6 children, and the probability that a particular child is a girl is 1/2

Find the probabilities that the 6-child family has the following children.

A.
All girls

B.
No more than two boys

ANSWER:
A.
1/64 = .016

B.
11/32 = .344

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Posted on May 14, 2009 at 12:59:25PM

A:
Preview: ... ies that the 6-child family has the following children. A ...

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Posted on May 14, 2009 at 1:00:36PM

A:
Preview: ... d part throug ...

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Posted on May 14, 2009 at 1:01:09PM

A:
Preview: ... are independent this is P(all girls) = P(child 1 = girl) * P(child 2 = girl) * P(child 3 = girl) * P(child 4 = girl) * P(child 5 = girl) * P(child 6 = girl) = 1/2*1/2*1/2*1/2*1/2*1/2 = 1/2^6 = 1/64 B. You can break this probability d ...

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