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| mdld from Drexel University, Philadelphia, PA - Mathematics & Computer Science |
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| Comments for mdld1-10 of 47 | Next | |||||
| Date | Price | Grade | Comment | Question | User |
|---|---|---|---|---|---|
| Nov 20, 2009 at 10:21:11PM | $3.00 | A | Thanks! | #213716 | winterbaby73 |
| Nov 19, 2009 at 5:51:31PM | $1.00 | A | good work | #212681 | montie |
| Nov 09, 2009 at 11:09:07PM | $0.75 | A | Thank You | #205506 | jwgill2 |
| Oct 30, 2009 at 12:15:35PM | $2.00 | A | ! | #197713 | chemtard |
| Oct 30, 2009 at 12:15:19PM | $1.00 | A | ! | #197725 | chemtard |
| Oct 29, 2009 at 11:29:41PM | $3.00 | A | Great! thank you. | #197366 | mocca732 |
| Oct 29, 2009 at 9:21:57PM | $0.75 | A | Good Work | #197084 | jwgill2 |
| Oct 29, 2009 at 9:19:59PM | $0.75 | A | Nice | #197080 | jwgill2 |
| Oct 26, 2009 at 5:40:13PM | $1.00 | A | Thank you, that was wonderful! I understand alot more by this answer, mdld replied: Thanks. Please remove the line So 7.0 g of KClO3 is (7.0 g/122.55 g/mol) = 0.057 mol It's not useful. |
#194858 | Becky_Johnson |
| Oct 23, 2009 at 10:55:42PM | $1.00 | A | mdld answered my question Ankit took 5 dollars and gave me nothing | #194144 | merlin52 |
